Integrand size = 28, antiderivative size = 28 \[ \int \frac {\sqrt {1-c^2 x^2}}{x (a+b \arcsin (c x))} \, dx=\frac {\operatorname {CosIntegral}\left (\frac {a+b \arcsin (c x)}{b}\right ) \sin \left (\frac {a}{b}\right )}{b}-\frac {\cos \left (\frac {a}{b}\right ) \text {Si}\left (\frac {a+b \arcsin (c x)}{b}\right )}{b}+\text {Int}\left (\frac {1}{x \sqrt {1-c^2 x^2} (a+b \arcsin (c x))},x\right ) \]
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Not integrable
Time = 0.26 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.00, number of steps used = 0, number of rules used = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int \frac {\sqrt {1-c^2 x^2}}{x (a+b \arcsin (c x))} \, dx=\int \frac {\sqrt {1-c^2 x^2}}{x (a+b \arcsin (c x))} \, dx \]
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Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {1}{x \sqrt {1-c^2 x^2} (a+b \arcsin (c x))}-\frac {c^2 x}{\sqrt {1-c^2 x^2} (a+b \arcsin (c x))}\right ) \, dx \\ & = -\left (c^2 \int \frac {x}{\sqrt {1-c^2 x^2} (a+b \arcsin (c x))} \, dx\right )+\int \frac {1}{x \sqrt {1-c^2 x^2} (a+b \arcsin (c x))} \, dx \\ & = \frac {\text {Subst}\left (\int \frac {\sin \left (\frac {a}{b}-\frac {x}{b}\right )}{x} \, dx,x,a+b \arcsin (c x)\right )}{b}+\int \frac {1}{x \sqrt {1-c^2 x^2} (a+b \arcsin (c x))} \, dx \\ & = -\frac {\cos \left (\frac {a}{b}\right ) \text {Subst}\left (\int \frac {\sin \left (\frac {x}{b}\right )}{x} \, dx,x,a+b \arcsin (c x)\right )}{b}+\frac {\sin \left (\frac {a}{b}\right ) \text {Subst}\left (\int \frac {\cos \left (\frac {x}{b}\right )}{x} \, dx,x,a+b \arcsin (c x)\right )}{b}+\int \frac {1}{x \sqrt {1-c^2 x^2} (a+b \arcsin (c x))} \, dx \\ & = \frac {\operatorname {CosIntegral}\left (\frac {a+b \arcsin (c x)}{b}\right ) \sin \left (\frac {a}{b}\right )}{b}-\frac {\cos \left (\frac {a}{b}\right ) \text {Si}\left (\frac {a+b \arcsin (c x)}{b}\right )}{b}+\int \frac {1}{x \sqrt {1-c^2 x^2} (a+b \arcsin (c x))} \, dx \\ \end{align*}
Not integrable
Time = 3.49 (sec) , antiderivative size = 30, normalized size of antiderivative = 1.07 \[ \int \frac {\sqrt {1-c^2 x^2}}{x (a+b \arcsin (c x))} \, dx=\int \frac {\sqrt {1-c^2 x^2}}{x (a+b \arcsin (c x))} \, dx \]
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Not integrable
Time = 0.18 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.93
\[\int \frac {\sqrt {-c^{2} x^{2}+1}}{x \left (a +b \arcsin \left (c x \right )\right )}d x\]
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Not integrable
Time = 0.24 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.00 \[ \int \frac {\sqrt {1-c^2 x^2}}{x (a+b \arcsin (c x))} \, dx=\int { \frac {\sqrt {-c^{2} x^{2} + 1}}{{\left (b \arcsin \left (c x\right ) + a\right )} x} \,d x } \]
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Not integrable
Time = 0.76 (sec) , antiderivative size = 26, normalized size of antiderivative = 0.93 \[ \int \frac {\sqrt {1-c^2 x^2}}{x (a+b \arcsin (c x))} \, dx=\int \frac {\sqrt {- \left (c x - 1\right ) \left (c x + 1\right )}}{x \left (a + b \operatorname {asin}{\left (c x \right )}\right )}\, dx \]
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Not integrable
Time = 0.38 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.00 \[ \int \frac {\sqrt {1-c^2 x^2}}{x (a+b \arcsin (c x))} \, dx=\int { \frac {\sqrt {-c^{2} x^{2} + 1}}{{\left (b \arcsin \left (c x\right ) + a\right )} x} \,d x } \]
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Exception generated. \[ \int \frac {\sqrt {1-c^2 x^2}}{x (a+b \arcsin (c x))} \, dx=\text {Exception raised: TypeError} \]
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Not integrable
Time = 0.16 (sec) , antiderivative size = 28, normalized size of antiderivative = 1.00 \[ \int \frac {\sqrt {1-c^2 x^2}}{x (a+b \arcsin (c x))} \, dx=\int \frac {\sqrt {1-c^2\,x^2}}{x\,\left (a+b\,\mathrm {asin}\left (c\,x\right )\right )} \,d x \]
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